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131350035703 = 1011300495403
BaseRepresentation
bin111101001010100010…
…0100111110011110111
3110120001000021011110011
41322111010213303313
54123001102120303
6140201423041051
712326655611335
oct1722504476367
9416030234404
10131350035703
1150783741a17
1221558a40187
13c5037ab223
1465008d2b55
15363b63916d
hex1e95127cf7

131350035703 has 4 divisors (see below), whose sum is σ = 132650531208. Its totient is φ = 130049540200.

The previous prime is 131350035701. The next prime is 131350035709. The reversal of 131350035703 is 307530053131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131350035703 - 21 = 131350035701 is a prime.

It is a Smith number, since the sum of its digits (31) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131350035701) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 650247601 + ... + 650247802.

It is an arithmetic number, because the mean of its divisors is an integer number (33162632802).

Almost surely, 2131350035703 is an apocalyptic number.

131350035703 is a deficient number, since it is larger than the sum of its proper divisors (1300495505).

131350035703 is a wasteful number, since it uses less digits than its factorization.

131350035703 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1300495504.

The product of its (nonzero) digits is 14175, while the sum is 31.

Adding to 131350035703 its reverse (307530053131), we get a palindrome (438880088834).

The spelling of 131350035703 in words is "one hundred thirty-one billion, three hundred fifty million, thirty-five thousand, seven hundred three".

Divisors: 1 101 1300495403 131350035703