Base | Representation |
---|---|
bin | 111101001010100010… |
… | …0100111110100011101 |
3 | 110120001000021011111120 |
4 | 1322111010213310131 |
5 | 4123001102120431 |
6 | 140201423041153 |
7 | 12326655611421 |
oct | 1722504476435 |
9 | 416030234446 |
10 | 131350035741 |
11 | 50783741a51 |
12 | 21558a401b9 |
13 | c5037ab252 |
14 | 65008d2b81 |
15 | 363b639196 |
hex | 1e95127d1d |
131350035741 has 4 divisors (see below), whose sum is σ = 175133380992. Its totient is φ = 87566690492.
The previous prime is 131350035731. The next prime is 131350035757. The reversal of 131350035741 is 147530053131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 131350035741 - 25 = 131350035709 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131350035701) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21891672621 + ... + 21891672626.
It is an arithmetic number, because the mean of its divisors is an integer number (43783345248).
Almost surely, 2131350035741 is an apocalyptic number.
It is an amenable number.
131350035741 is a deficient number, since it is larger than the sum of its proper divisors (43783345251).
131350035741 is an equidigital number, since it uses as much as digits as its factorization.
131350035741 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43783345250.
The product of its (nonzero) digits is 18900, while the sum is 33.
Adding to 131350035741 its reverse (147530053131), we get a palindrome (278880088872).
The spelling of 131350035741 in words is "one hundred thirty-one billion, three hundred fifty million, thirty-five thousand, seven hundred forty-one".
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