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13135013035 = 52627002607
BaseRepresentation
bin11000011101110100…
…00110010010101011
31020220101211210112021
430032322012102223
5203400030404120
610011212525311
7643332524434
oct141672062253
936811753467
1013135013035
115630410781
122666a80837
131314354181
148c867248b
1551d220aaa
hex30ee864ab

13135013035 has 4 divisors (see below), whose sum is σ = 15762015648. Its totient is φ = 10508010424.

The previous prime is 13135013009. The next prime is 13135013051. The reversal of 13135013035 is 53031053131.

13135013035 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13135013035 is a prime.

It is a super-2 number, since 2×131350130352 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1313501299 + ... + 1313501308.

It is an arithmetic number, because the mean of its divisors is an integer number (3940503912).

Almost surely, 213135013035 is an apocalyptic number.

13135013035 is a deficient number, since it is larger than the sum of its proper divisors (2627002613).

13135013035 is an equidigital number, since it uses as much as digits as its factorization.

13135013035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2627002612.

The product of its (nonzero) digits is 2025, while the sum is 25.

Adding to 13135013035 its reverse (53031053131), we get a palindrome (66166066166).

The spelling of 13135013035 in words is "thirteen billion, one hundred thirty-five million, thirteen thousand, thirty-five".

Divisors: 1 5 2627002607 13135013035