Base | Representation |
---|---|
bin | 11101110111011001010110… |
… | …000001111101111001110111 |
3 | 122020001221122121211022011122 |
4 | 131313121112001331321313 |
5 | 114204020033044440201 |
6 | 1143205230154054155 |
7 | 36444506514445424 |
oct | 3567312601757167 |
9 | 566057577738148 |
10 | 131350133202551 |
11 | 389413079a151a |
12 | 12894651a1a35b |
13 | 583a358bb9703 |
14 | 2461547a2cd4b |
15 | 102bab98c5e1b |
hex | 77765607de77 |
131350133202551 has 8 divisors (see below), whose sum is σ = 135879807488880. Its totient is φ = 126820482872832.
The previous prime is 131350133202527. The next prime is 131350133202593. The reversal of 131350133202551 is 155202331053131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 131350133202551 - 222 = 131350129008247 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131350133202521) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5541911 + ... + 17129303.
It is an arithmetic number, because the mean of its divisors is an integer number (16984975936110).
Almost surely, 2131350133202551 is an apocalyptic number.
131350133202551 is a deficient number, since it is larger than the sum of its proper divisors (4529674286329).
131350133202551 is a wasteful number, since it uses less digits than its factorization.
131350133202551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11978305.
The product of its (nonzero) digits is 40500, while the sum is 35.
Adding to 131350133202551 its reverse (155202331053131), we get a palindrome (286552464255682).
The spelling of 131350133202551 in words is "one hundred thirty-one trillion, three hundred fifty billion, one hundred thirty-three million, two hundred two thousand, five hundred fifty-one".
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