Base | Representation |
---|---|
bin | 11000011101110100… |
… | …11100000011001001 |
3 | 1020220102000022202221 |
4 | 30032322130003021 |
5 | 203400041232103 |
6 | 10011214454041 |
7 | 643333345315 |
oct | 141672340311 |
9 | 36812008687 |
10 | 13135102153 |
11 | 5630471728 |
12 | 2666b04321 |
13 | 13143858c4 |
14 | 8c8696b45 |
15 | 51d23c1bd |
hex | 30ee9c0c9 |
13135102153 has 12 divisors (see below), whose sum is σ = 13613520960. Its totient is φ = 12672971696.
The previous prime is 13135102151. The next prime is 13135102171. The reversal of 13135102153 is 35120153131.
It is not a de Polignac number, because 13135102153 - 21 = 13135102151 is a prime.
It is a super-3 number, since 3×131351021533 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13135102151) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1346628 + ... + 1356346.
It is an arithmetic number, because the mean of its divisors is an integer number (1134460080).
Almost surely, 213135102153 is an apocalyptic number.
It is an amenable number.
13135102153 is a deficient number, since it is larger than the sum of its proper divisors (478418807).
13135102153 is an equidigital number, since it uses as much as digits as its factorization.
13135102153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11384 (or 11355 counting only the distinct ones).
The product of its (nonzero) digits is 1350, while the sum is 25.
Adding to 13135102153 its reverse (35120153131), we get a palindrome (48255255284).
The spelling of 13135102153 in words is "thirteen billion, one hundred thirty-five million, one hundred two thousand, one hundred fifty-three".
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