131352414225343 has 4 divisors (see below), whose sum is σ = 131353938634248. Its totient is φ = 131350889816440.

The previous prime is 131352414225323. The next prime is 131352414225359. The reversal of 131352414225343 is 343522414253131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131352414225343 - 2⁹ = 131352414224831 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131352414225343.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131352414225323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 762075196 + ... + 762247537.

It is an arithmetic number, because the mean of its divisors is an integer number (32838484658562).

Almost surely, 2^{131352414225343} is an apocalyptic number.

131352414225343 is a deficient number, since it is larger than the sum of its proper divisors (1524408905).

131352414225343 is an equidigital number, since it uses as much as digits as its factorization.

131352414225343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1524408904.

The product of its digits is 1036800, while the sum is 43.

Adding to 131352414225343 its reverse (343522414253131), we get a palindrome (474874828478474).

The spelling of 131352414225343 in words is "one hundred thirty-one trillion, three hundred fifty-two billion, four hundred fourteen million, two hundred twenty-five thousand, three hundred forty-three".