Base | Representation |
---|---|
bin | 11101110111011100001000… |
… | …010101011001010111010101 |
3 | 122020002020101002202002012010 |
4 | 131313130020111121113111 |
5 | 114204042144401441323 |
6 | 1143210443055014433 |
7 | 36444643610320140 |
oct | 3567341025312725 |
9 | 566066332662163 |
10 | 131353124640213 |
11 | 38942602543953 |
12 | 1289514780a419 |
13 | 583a714893878 |
14 | 246174d047057 |
15 | 102bbe2327c93 |
hex | 7777085595d5 |
131353124640213 has 8 divisors (see below), whose sum is σ = 200157142308928. Its totient is φ = 75058928365824.
The previous prime is 131353124640211. The next prime is 131353124640229. The reversal of 131353124640213 is 312046421353131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 131353124640213 - 21 = 131353124640211 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131353124640211) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3127455348556 + ... + 3127455348597.
It is an arithmetic number, because the mean of its divisors is an integer number (25019642788616).
Almost surely, 2131353124640213 is an apocalyptic number.
It is an amenable number.
131353124640213 is a deficient number, since it is larger than the sum of its proper divisors (68804017668715).
131353124640213 is an equidigital number, since it uses as much as digits as its factorization.
131353124640213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6254910697163.
The product of its (nonzero) digits is 155520, while the sum is 39.
Adding to 131353124640213 its reverse (312046421353131), we get a palindrome (443399545993344).
The spelling of 131353124640213 in words is "one hundred thirty-one trillion, three hundred fifty-three billion, one hundred twenty-four million, six hundred forty thousand, two hundred thirteen".
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