Base | Representation |
---|---|
bin | 11000011101111000… |
… | …10100111111101011 |
3 | 1020220102221111022212 |
4 | 30032330110333223 |
5 | 203400203110142 |
6 | 10011233235335 |
7 | 643340510522 |
oct | 141674247753 |
9 | 36812844285 |
10 | 13135597547 |
11 | 563077a946 |
12 | 2667102b4b |
13 | 13144ca237 |
14 | 8c87854b9 |
15 | 51d2d8d82 |
hex | 30ef14feb |
13135597547 has 4 divisors (see below), whose sum is σ = 13235869416. Its totient is φ = 13035325680.
The previous prime is 13135597529. The next prime is 13135597561. The reversal of 13135597547 is 74579553131.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 74579553131 = 41 ⋅1819013491.
It is a cyclic number.
It is not a de Polignac number, because 13135597547 - 26 = 13135597483 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13135597495 and 13135597504.
It is not an unprimeable number, because it can be changed into a prime (13135597147) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50135738 + ... + 50135999.
It is an arithmetic number, because the mean of its divisors is an integer number (3308967354).
Almost surely, 213135597547 is an apocalyptic number.
13135597547 is a deficient number, since it is larger than the sum of its proper divisors (100271869).
13135597547 is a wasteful number, since it uses less digits than its factorization.
13135597547 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 100271868.
The product of its digits is 1984500, while the sum is 50.
The spelling of 13135597547 in words is "thirteen billion, one hundred thirty-five million, five hundred ninety-seven thousand, five hundred forty-seven".
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