Base | Representation |
---|---|
bin | 10011000111010110100… |
… | …010010100001010101011 |
3 | 11122120112120001120111102 |
4 | 103013112202110022223 |
5 | 133010134433020003 |
6 | 2443235414352015 |
7 | 163621230464621 |
oct | 23072642241253 |
9 | 4576476046442 |
10 | 1313564345003 |
11 | 467096912379 |
12 | 1926b205b60b |
13 | 96b3a38caa1 |
14 | 47810c59511 |
15 | 2427eba0588 |
hex | 131d68942ab |
1313564345003 has 16 divisors (see below), whose sum is σ = 1379574451776. Its totient is φ = 1248297747840.
The previous prime is 1313564344999. The next prime is 1313564345017. The reversal of 1313564345003 is 3005434653131.
It is a cyclic number.
It is not a de Polignac number, because 1313564345003 - 22 = 1313564344999 is a prime.
It is a super-2 number, since 2×13135643450032 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1313564345063) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 39202325 + ... + 39235817.
It is an arithmetic number, because the mean of its divisors is an integer number (86223403236).
Almost surely, 21313564345003 is an apocalyptic number.
1313564345003 is a deficient number, since it is larger than the sum of its proper divisors (66010106773).
1313564345003 is a wasteful number, since it uses less digits than its factorization.
1313564345003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 44534.
The product of its (nonzero) digits is 194400, while the sum is 38.
Adding to 1313564345003 its reverse (3005434653131), we get a palindrome (4318998998134).
The spelling of 1313564345003 in words is "one trillion, three hundred thirteen billion, five hundred sixty-four million, three hundred forty-five thousand, three".
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