Base | Representation |
---|---|
bin | 111101001011000011… |
… | …0010111101001111011 |
3 | 110120002012200210212210 |
4 | 1322112012113221323 |
5 | 4123020010133120 |
6 | 140203240310203 |
7 | 12330255244200 |
oct | 1722606275173 |
9 | 416065623783 |
10 | 131367271035 |
11 | 507924440a0 |
12 | 21562772363 |
13 | c507234150 |
14 | 6502cdbca7 |
15 | 363cde0ce0 |
hex | 1e96197a7b |
131367271035 has 192 divisors, whose sum is σ = 289958828544. Its totient is φ = 49919385600.
The previous prime is 131367270953. The next prime is 131367271067. The reversal of 131367271035 is 530172763131.
It is a happy number.
It is not a de Polignac number, because 131367271035 - 210 = 131367270011 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (39).
It is a junction number, because it is equal to n+sod(n) for n = 131367270984 and 131367271002.
It is an unprimeable number.
It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 11240395 + ... + 11252075.
It is an arithmetic number, because the mean of its divisors is an integer number (1510202232).
Almost surely, 2131367271035 is an apocalyptic number.
131367271035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
131367271035 is an abundant number, since it is smaller than the sum of its proper divisors (158591557509).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131367271035 is a wasteful number, since it uses less digits than its factorization.
131367271035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11834 (or 11827 counting only the distinct ones).
The product of its (nonzero) digits is 79380, while the sum is 39.
The spelling of 131367271035 in words is "one hundred thirty-one billion, three hundred sixty-seven million, two hundred seventy-one thousand, thirty-five".
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