Base | Representation |
---|---|
bin | 111101001011010101… |
… | …0100000101111111111 |
3 | 110120002212112011100211 |
4 | 1322112222200233333 |
5 | 4123024421323341 |
6 | 140204215333251 |
7 | 12330431624356 |
oct | 1722652405777 |
9 | 416085464324 |
10 | 131376745471 |
11 | 50797825404 |
12 | 21565981227 |
13 | c5091a071a |
14 | 650428699d |
15 | 363db63181 |
hex | 1e96aa0bff |
131376745471 has 4 divisors (see below), whose sum is σ = 131381891632. Its totient is φ = 131371599312.
The previous prime is 131376745463. The next prime is 131376745483. The reversal of 131376745471 is 174547673131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131376745471 - 23 = 131376745463 is a prime.
It is a super-3 number, since 3×1313767454713 (a number of 34 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131376745421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2534595 + ... + 2585908.
It is an arithmetic number, because the mean of its divisors is an integer number (32845472908).
Almost surely, 2131376745471 is an apocalyptic number.
131376745471 is a deficient number, since it is larger than the sum of its proper divisors (5146161).
131376745471 is an equidigital number, since it uses as much as digits as its factorization.
131376745471 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5146160.
The product of its digits is 1481760, while the sum is 49.
The spelling of 131376745471 in words is "one hundred thirty-one billion, three hundred seventy-six million, seven hundred forty-five thousand, four hundred seventy-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •