Base | Representation |
---|---|
bin | 1011111100101111000100… |
… | …0110110011010001111011 |
3 | 1201111222121122111101122120 |
4 | 2333023301012303101323 |
5 | 3210223214100130011 |
6 | 43535312244052323 |
7 | 2524123152424206 |
oct | 277136106632173 |
9 | 51458548441576 |
10 | 13138055083131 |
11 | 42058aa64a020 |
12 | 15822b00940a3 |
13 | 743bb461b014 |
14 | 335c5721693d |
15 | 17bb3e776a06 |
hex | bf2f11b347b |
13138055083131 has 32 divisors (see below), whose sum is σ = 19322534092032. Its totient is φ = 7874177525760.
The previous prime is 13138055083103. The next prime is 13138055083147.
13138055083131 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 13138055083131 - 219 = 13138054558843 is a prime.
It is a super-2 number, since 2×131380550831312 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13138055083151) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2324590 + ... + 5628483.
It is an arithmetic number, because the mean of its divisors is an integer number (603829190376).
Almost surely, 213138055083131 is an apocalyptic number.
13138055083131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13138055083131 is a deficient number, since it is larger than the sum of its proper divisors (6184479008901).
13138055083131 is a wasteful number, since it uses less digits than its factorization.
13138055083131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7953643.
The product of its (nonzero) digits is 129600, while the sum is 42.
It can be divided in two parts, 1313805 and 5083131, that added together give a palindrome (6396936).
The spelling of 13138055083131 in words is "thirteen trillion, one hundred thirty-eight billion, fifty-five million, eighty-three thousand, one hundred thirty-one".
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