Base | Representation |
---|---|
bin | 1011111100110110010100… |
… | …0010111010100000111001 |
3 | 1201112011122012121122111210 |
4 | 2333031211002322200321 |
5 | 3210241210024034431 |
6 | 43540233251113333 |
7 | 2524222312011615 |
oct | 277154502724071 |
9 | 51464565548453 |
10 | 13140000221241 |
11 | 4206708625083 |
12 | 15827535a2849 |
13 | 7441345c700a |
14 | 335d9d6b0345 |
15 | 17bc053edd46 |
hex | bf3650ba839 |
13140000221241 has 32 divisors (see below), whose sum is σ = 17614812676608. Its totient is φ = 8712702416000.
The previous prime is 13140000221239. The next prime is 13140000221261. The reversal of 13140000221241 is 14212200004131.
It is a cyclic number.
It is not a de Polignac number, because 13140000221241 - 21 = 13140000221239 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13140000221261) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2744931850 + ... + 2744936636.
It is an arithmetic number, because the mean of its divisors is an integer number (550462896144).
Almost surely, 213140000221241 is an apocalyptic number.
It is an amenable number.
13140000221241 is a deficient number, since it is larger than the sum of its proper divisors (4474812455367).
13140000221241 is a wasteful number, since it uses less digits than its factorization.
13140000221241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9461.
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 13140000221241 its reverse (14212200004131), we get a palindrome (27352200225372).
The spelling of 13140000221241 in words is "thirteen trillion, one hundred forty billion, two hundred twenty-one thousand, two hundred forty-one".
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