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1314000230041 = 4727957451703
BaseRepresentation
bin10011000111110000100…
…001000101011010011001
311122121122221020211100201
4103013300201011122121
5133012033024330131
62443350545102201
7163635102445522
oct23076041053231
94577587224321
101314000230041
1146729a968244
121927b4027961
1396ba9786c25
1447852ac1849
15242a80a1761
hex131f0845699

1314000230041 has 4 divisors (see below), whose sum is σ = 1341957681792. Its totient is φ = 1286042778292.

The previous prime is 1314000229987. The next prime is 1314000230051. The reversal of 1314000230041 is 1400320004131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1314000230041 - 211 = 1314000227993 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1314000230051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13978725805 + ... + 13978725898.

It is an arithmetic number, because the mean of its divisors is an integer number (335489420448).

Almost surely, 21314000230041 is an apocalyptic number.

It is an amenable number.

1314000230041 is a deficient number, since it is larger than the sum of its proper divisors (27957451751).

1314000230041 is an equidigital number, since it uses as much as digits as its factorization.

1314000230041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27957451750.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 1314000230041 its reverse (1400320004131), we get a palindrome (2714320234172).

The spelling of 1314000230041 in words is "one trillion, three hundred fourteen billion, two hundred thirty thousand, forty-one".

Divisors: 1 47 27957451703 1314000230041