1314000343 has 4 divisors (see below), whose sum is σ = 1314259240. Its totient is φ = 1313741448.

The previous prime is 1314000323. The next prime is 1314000371. The reversal of 1314000343 is 3430004131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3430004131 = 19403 ⋅176777.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1314000343 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1314000343.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1314000323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 121680 + ... + 132037.

It is an arithmetic number, because the mean of its divisors is an integer number (328564810).

Almost surely, 2^1314000343 is an apocalyptic number.

1314000343 is a deficient number, since it is larger than the sum of its proper divisors (258897).

1314000343 is an equidigital number, since it uses as much as digits as its factorization.

1314000343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 258896.

The product of its (nonzero) digits is 432, while the sum is 19.

The square root of 1314000343 is about 36249.1426519304. The cubic root of 1314000343 is about 1095.2968185432.

Adding to 1314000343 its reverse (3430004131), we get a palindrome (4744004474).

The spelling of 1314000343 in words is "one billion, three hundred fourteen million, three hundred forty-three", and thus it is an aban number.