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13140033403 = 72713776957
BaseRepresentation
bin11000011110011010…
…01111111101111011
31020220202021212011211
430033031033331323
5203402322032103
610011512303551
7643423304200
oct141715177573
936822255154
1013140033403
11563322a642
1226686a1bb7
1313153c12c3
148c91bbca7
1551d8b336d
hex30f34ff7b

13140033403 has 12 divisors (see below), whose sum is σ = 15500635632. Its totient is φ = 11104250640.

The previous prime is 13140033391. The next prime is 13140033407. The reversal of 13140033403 is 30433004131.

It is a happy number.

It is a de Polignac number, because none of the positive numbers 2k-13140033403 is a prime.

It is a super-3 number, since 3×131400334033 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13140033407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1885000 + ... + 1891957.

It is an arithmetic number, because the mean of its divisors is an integer number (1291719636).

Almost surely, 213140033403 is an apocalyptic number.

13140033403 is a deficient number, since it is larger than the sum of its proper divisors (2360602229).

13140033403 is an equidigital number, since it uses as much as digits as its factorization.

13140033403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3777042 (or 3777035 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 22.

Adding to 13140033403 its reverse (30433004131), we get a palindrome (43573037534).

The spelling of 13140033403 in words is "thirteen billion, one hundred forty million, thirty-three thousand, four hundred three".

Divisors: 1 7 49 71 497 3479 3776957 26438699 185070893 268163947 1877147629 13140033403