1314012420043 has 4 divisors (see below), whose sum is σ = 1315330387360. Its totient is φ = 1312694452728.

The previous prime is 1314012420041. The next prime is 1314012420047. The reversal of 1314012420043 is 3400242104131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1314012420043 - 2¹ = 1314012420041 is a prime.

It is a super-3 number, since 3×1314012420043³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1314012420041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 658982163 + ... + 658984156.

It is an arithmetic number, because the mean of its divisors is an integer number (328832596840).

Almost surely, 2^{1314012420043} is an apocalyptic number.

1314012420043 is a deficient number, since it is larger than the sum of its proper divisors (1317967317).

1314012420043 is an equidigital number, since it uses as much as digits as its factorization.

1314012420043 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1317967316.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1314012420043 its reverse (3400242104131), we get a palindrome (4714254524174).

The spelling of 1314012420043 in words is "one trillion, three hundred fourteen billion, twelve million, four hundred twenty thousand, forty-three".