13140242325441 has 64 divisors (see below), whose sum is σ = 25547976345600. Its totient is φ = 6466831473600.

The previous prime is 13140242325439. The next prime is 13140242325449. The reversal of 13140242325441 is 14452324204131.

13140242325441 is a `hidden beast` number, since 1 + 3 + 1 + 40 + 2 + 42 + 32 + 544 + 1 = 666.

It is not a de Polignac number, because 13140242325441 - 2¹ = 13140242325439 is a prime.

It is a super-2 number, since 2×13140242325441² (a number of 27 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13140242325396 and 13140242325405.

It is not an unprimeable number, because it can be changed into a prime (13140242325449) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 166288470 + ... + 166367471.

It is an arithmetic number, because the mean of its divisors is an integer number (399187130400).

Almost surely, 2^{13140242325441} is an apocalyptic number.

13140242325441 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13140242325441 is a deficient number, since it is larger than the sum of its proper divisors (12407734020159).

13140242325441 is a wasteful number, since it uses less digits than its factorization.

13140242325441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 332655987 (or 332655981 counting only the distinct ones).

The product of its (nonzero) digits is 92160, while the sum is 36.

Adding to 13140242325441 its reverse (14452324204131), we get a palindrome (27592566529572).

The spelling of 13140242325441 in words is "thirteen trillion, one hundred forty billion, two hundred forty-two million, three hundred twenty-five thousand, four hundred forty-one".