Base | Representation |
---|---|
bin | 11101111000001010110111… |
… | …000001010010101100000001 |
3 | 122020021000212220120121211021 |
4 | 131320022313001102230001 |
5 | 114210402424301214131 |
6 | 1143245502003345441 |
7 | 36451401162121114 |
oct | 3570126701225401 |
9 | 566230786517737 |
10 | 131403300023041 |
11 | 38961910205692 |
12 | 128a2a0b382281 |
13 | 584237ca7b9c7 |
14 | 2463d4cb8c57b |
15 | 102d17c2b2e11 |
hex | 7782b7052b01 |
131403300023041 has 4 divisors (see below), whose sum is σ = 131403402542932. Its totient is φ = 131403197503152.
The previous prime is 131403300022997. The next prime is 131403300023101. The reversal of 131403300023041 is 140320003304131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 98472676755600 + 32930623267441 = 9923340^2 + 5738521^2 .
It is a cyclic number.
It is not a de Polignac number, because 131403300023041 - 27 = 131403300022913 is a prime.
It is a super-2 number, since 2×1314033000230412 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 131403300022997 and 131403300023015.
It is not an unprimeable number, because it can be changed into a prime (131403300423041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 49312686 + ... + 51909031.
It is an arithmetic number, because the mean of its divisors is an integer number (32850850635733).
Almost surely, 2131403300023041 is an apocalyptic number.
It is an amenable number.
131403300023041 is a deficient number, since it is larger than the sum of its proper divisors (102519891).
131403300023041 is a wasteful number, since it uses less digits than its factorization.
131403300023041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 102519890.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 131403300023041 its reverse (140320003304131), we get a palindrome (271723303327172).
The spelling of 131403300023041 in words is "one hundred thirty-one trillion, four hundred three billion, three hundred million, twenty-three thousand, forty-one".
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