131403312020113 has 4 divisors (see below), whose sum is σ = 150175213737280. Its totient is φ = 112631410302948.

The previous prime is 131403312020107. The next prime is 131403312020131. The reversal of 131403312020113 is 311020213304131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131403312020113 - 2⁹ = 131403312019601 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131403312026113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9385950858573 + ... + 9385950858586.

It is an arithmetic number, because the mean of its divisors is an integer number (37543803434320).

Almost surely, 2^{131403312020113} is an apocalyptic number.

It is an amenable number.

131403312020113 is a deficient number, since it is larger than the sum of its proper divisors (18771901717167).

131403312020113 is an equidigital number, since it uses as much as digits as its factorization.

131403312020113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18771901717166.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 131403312020113 its reverse (311020213304131), we get a palindrome (442423525324244).

The spelling of 131403312020113 in words is "one hundred thirty-one trillion, four hundred three billion, three hundred twelve million, twenty thousand, one hundred thirteen".