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131403341103403 = 709185336165167
BaseRepresentation
bin11101111000001010111001…
…011110000000000100101011
3122020021000222202212201111011
4131320022321132000010223
5114210403020310302103
61143245510032044351
736451402201235665
oct3570127136000453
9566230882781434
10131403341103403
11389619314139a6
12128a2a210936b7
135842388433205
142463d54403535
15102d180bc9d6d
hex7782b978012b

131403341103403 has 4 divisors (see below), whose sum is σ = 131588677269280. Its totient is φ = 131218004937528.

The previous prime is 131403341103371. The next prime is 131403341103407. The reversal of 131403341103403 is 304301143304131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131403341103403 - 25 = 131403341103371 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131403341103407) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 92668081875 + ... + 92668083292.

It is an arithmetic number, because the mean of its divisors is an integer number (32897169317320).

Almost surely, 2131403341103403 is an apocalyptic number.

131403341103403 is a deficient number, since it is larger than the sum of its proper divisors (185336165877).

131403341103403 is an equidigital number, since it uses as much as digits as its factorization.

131403341103403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 185336165876.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 131403341103403 its reverse (304301143304131), we get a palindrome (435704484407534).

The spelling of 131403341103403 in words is "one hundred thirty-one trillion, four hundred three billion, three hundred forty-one million, one hundred three thousand, four hundred three".

Divisors: 1 709 185336165167 131403341103403