Base | Representation |
---|---|
bin | 1011111100110111100101… |
… | …0011011100110100110111 |
3 | 1201112012111220011022002001 |
4 | 2333031321103130310313 |
5 | 3210242404031203112 |
6 | 43540331112000131 |
7 | 2524233606644152 |
oct | 277157123346467 |
9 | 51465456138061 |
10 | 13140340100407 |
11 | 4206872467353 |
12 | 1582829390047 |
13 | 744189b48650 |
14 | 335dd28a4c99 |
15 | 17bc25188c57 |
hex | bf3794dcd37 |
13140340100407 has 4 divisors (see below), whose sum is σ = 14151135492760. Its totient is φ = 12129544708056.
The previous prime is 13140340100387. The next prime is 13140340100417. The reversal of 13140340100407 is 70400104304131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13140340100407 - 235 = 13105980362039 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13140340100417) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 505397696157 + ... + 505397696182.
It is an arithmetic number, because the mean of its divisors is an integer number (3537783873190).
Almost surely, 213140340100407 is an apocalyptic number.
13140340100407 is a deficient number, since it is larger than the sum of its proper divisors (1010795392353).
13140340100407 is a wasteful number, since it uses less digits than its factorization.
13140340100407 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1010795392352.
The product of its (nonzero) digits is 4032, while the sum is 28.
Adding to 13140340100407 its reverse (70400104304131), we get a palindrome (83540444404538).
The spelling of 13140340100407 in words is "thirteen trillion, one hundred forty billion, three hundred forty million, one hundred thousand, four hundred seven".
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