Base | Representation |
---|---|
bin | 1011111100110111100101… |
… | …1111011011011011010001 |
3 | 1201112012112010001211100010 |
4 | 2333031321133123123101 |
5 | 3210242410332143101 |
6 | 43540331303145133 |
7 | 2524233645432516 |
oct | 277157137333321 |
9 | 51465463054303 |
10 | 13140343240401 |
11 | 4206874211493 |
12 | 158282a4451a9 |
13 | 74418a6a7930 |
14 | 335dd308130d |
15 | 17bc255a92d6 |
hex | bf3797db6d1 |
13140343240401 has 16 divisors (see below), whose sum is σ = 18868253455296. Its totient is φ = 8086335804096.
The previous prime is 13140343240391. The next prime is 13140343240481. The reversal of 13140343240401 is 10404234304131.
It is not a de Polignac number, because 13140343240401 - 211 = 13140343238353 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (13140343240481) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16102051 + ... + 16898423.
It is an arithmetic number, because the mean of its divisors is an integer number (1179265840956).
Almost surely, 213140343240401 is an apocalyptic number.
It is an amenable number.
13140343240401 is a deficient number, since it is larger than the sum of its proper divisors (5727910214895).
13140343240401 is a wasteful number, since it uses less digits than its factorization.
13140343240401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1219472.
The product of its (nonzero) digits is 13824, while the sum is 30.
Adding to 13140343240401 its reverse (10404234304131), we get a palindrome (23544577544532).
The spelling of 13140343240401 in words is "thirteen trillion, one hundred forty billion, three hundred forty-three million, two hundred forty thousand, four hundred one".
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