13140352524661 has 4 divisors (see below), whose sum is σ = 13140415420524. Its totient is φ = 13140289628800.

The previous prime is 13140352524631. The next prime is 13140352524667. The reversal of 13140352524661 is 16642525304131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 11481423980625 + 1658928544036 = 3388425^2 + 1287994^2 .

It is a cyclic number.

It is not a de Polignac number, because 13140352524661 - 2¹¹ = 13140352522613 is a prime.

It is a super-2 number, since 2×13140352524661² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13140352524667) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31133500 + ... + 31552741.

It is an arithmetic number, because the mean of its divisors is an integer number (3285103855131).

Almost surely, 2^{13140352524661} is an apocalyptic number.

It is an amenable number.

13140352524661 is a deficient number, since it is larger than the sum of its proper divisors (62895863).

13140352524661 is an equidigital number, since it uses as much as digits as its factorization.

13140352524661 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 62895862.

The product of its (nonzero) digits is 518400, while the sum is 43.

Adding to 13140352524661 its reverse (16642525304131), we get a palindrome (29782877828792).

The spelling of 13140352524661 in words is "thirteen trillion, one hundred forty billion, three hundred fifty-two million, five hundred twenty-four thousand, six hundred sixty-one".