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131404012031399 = 283464325130853
BaseRepresentation
bin11101111000001011100001…
…011101011000110110100111
3122020021002201112100101200012
4131320023201131120312213
5114210410404040001044
61143250100400240435
736451424626105202
oct3570134135306647
9566232645311605
10131404012031399
1138962146107048
12128a2b8991011b
135842464433b23
142463db9570939
15102d1bea5859e
hex7782e1758da7

131404012031399 has 4 divisors (see below), whose sum is σ = 131868337162536. Its totient is φ = 130939686900264.

The previous prime is 131404012031359. The next prime is 131404012031431. The reversal of 131404012031399 is 993130210404131.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2k-131404012031399 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131404012031359) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 232162565144 + ... + 232162565709.

It is an arithmetic number, because the mean of its divisors is an integer number (32967084290634).

Almost surely, 2131404012031399 is an apocalyptic number.

131404012031399 is a deficient number, since it is larger than the sum of its proper divisors (464325131137).

131404012031399 is an equidigital number, since it uses as much as digits as its factorization.

131404012031399 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 464325131136.

The product of its (nonzero) digits is 69984, while the sum is 41.

The spelling of 131404012031399 in words is "one hundred thirty-one trillion, four hundred four billion, twelve million, thirty-one thousand, three hundred ninety-nine".

Divisors: 1 283 464325130853 131404012031399