131404040103 has 8 divisors (see below), whose sum is σ = 200234727808. Its totient is φ = 75088022904.

The previous prime is 131404040099. The next prime is 131404040107. The reversal of 131404040103 is 301040404131.

It is an interprime number because it is at equal distance from previous prime (131404040099) and next prime (131404040107).

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 131404040103 - 2² = 131404040099 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (21), and also a Moran number because the ratio is a prime number: 6257335243 = 131404040103 / (1 + 3 + 1 + 4 + 0 + 4 + 0 + 4 + 0 + 1 + 0 + 3).

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131404040103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131404040107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3128667601 + ... + 3128667642.

It is an arithmetic number, because the mean of its divisors is an integer number (25029340976).

Almost surely, 2^131404040103 is an apocalyptic number.

131404040103 is a deficient number, since it is larger than the sum of its proper divisors (68830687705).

131404040103 is an equidigital number, since it uses as much as digits as its factorization.

131404040103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6257335253.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 131404040103 its reverse (301040404131), we get a palindrome (432444444234).

The spelling of 131404040103 in words is "one hundred thirty-one billion, four hundred four million, forty thousand, one hundred three".