131404040224013 has 4 divisors (see below), whose sum is σ = 132349393031520. Its totient is φ = 130458687416508.

The previous prime is 131404040224001. The next prime is 131404040224021. The reversal of 131404040224013 is 310422040404131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131404040224013 - 2¹⁸ = 131404039961869 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131404040224073) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 472676403545 + ... + 472676403822.

It is an arithmetic number, because the mean of its divisors is an integer number (33087348257880).

Almost surely, 2^{131404040224013} is an apocalyptic number.

It is an amenable number.

131404040224013 is a deficient number, since it is larger than the sum of its proper divisors (945352807507).

131404040224013 is an equidigital number, since it uses as much as digits as its factorization.

131404040224013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 945352807506.

The product of its (nonzero) digits is 9216, while the sum is 29.

Adding to 131404040224013 its reverse (310422040404131), we get a palindrome (441826080628144).

The spelling of 131404040224013 in words is "one hundred thirty-one trillion, four hundred four billion, forty million, two hundred twenty-four thousand, thirteen".