Base | Representation |
---|---|
bin | 111101001100001001… |
… | …0111001100110000011 |
3 | 110120011210000102201201 |
4 | 1322120102321212003 |
5 | 4123103423011321 |
6 | 140211034042031 |
7 | 12331213336063 |
oct | 1723022714603 |
9 | 416153012651 |
10 | 131404110211 |
11 | 508012159a0 |
12 | 21572b79317 |
13 | c511a6208a |
14 | 6507b6b3a3 |
15 | 364126b291 |
hex | 1e984b9983 |
131404110211 has 4 divisors (see below), whose sum is σ = 143349938424. Its totient is φ = 119458282000.
The previous prime is 131404110203. The next prime is 131404110221. The reversal of 131404110211 is 112011404131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131404110211 - 23 = 131404110203 is a prime.
It is not an unprimeable number, because it can be changed into a prime (131404110221) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5972914090 + ... + 5972914111.
It is an arithmetic number, because the mean of its divisors is an integer number (35837484606).
Almost surely, 2131404110211 is an apocalyptic number.
131404110211 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
131404110211 is a deficient number, since it is larger than the sum of its proper divisors (11945828213).
131404110211 is a wasteful number, since it uses less digits than its factorization.
131404110211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11945828212.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 131404110211 its reverse (112011404131), we get a palindrome (243415514342).
The spelling of 131404110211 in words is "one hundred thirty-one billion, four hundred four million, one hundred ten thousand, two hundred eleven".
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