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13140431133545 = 559218172041703
BaseRepresentation
bin1011111100110111111010…
…1110101101101101101001
31201112012202020110021001202
42333031332232231231221
53210243100332233140
643540344123053545
72524236063501662
oct277157656555551
951465666407052
1013140431133545
114206909893951
1215828539712b5
137441a296c901
14336000a00369
1517bc2d16b915
hexbf37ebadb69

13140431133545 has 16 divisors (see below), whose sum is σ = 16036523233920. Its totient is φ = 10333690833024.

The previous prime is 13140431133509. The next prime is 13140431133593. The reversal of 13140431133545 is 54533113404131.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13140431133545 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13140431133499 and 13140431133508.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5415164 + ... + 7456866.

It is an arithmetic number, because the mean of its divisors is an integer number (1002282702120).

Almost surely, 213140431133545 is an apocalyptic number.

It is an amenable number.

13140431133545 is a deficient number, since it is larger than the sum of its proper divisors (2896092100375).

13140431133545 is a wasteful number, since it uses less digits than its factorization.

13140431133545 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2063584.

The product of its (nonzero) digits is 129600, while the sum is 38.

Adding to 13140431133545 its reverse (54533113404131), we get a palindrome (67673544537676).

The spelling of 13140431133545 in words is "thirteen trillion, one hundred forty billion, four hundred thirty-one million, one hundred thirty-three thousand, five hundred forty-five".

Divisors: 1 5 59 295 21817 109085 1287203 2041703 6436015 10208515 120460477 602302385 44543834351 222719171755 2628086226709 13140431133545