131404313421301 has 4 divisors (see below), whose sum is σ = 132567183451692. Its totient is φ = 130241443390912.

The previous prime is 131404313421289. The next prime is 131404313421319. The reversal of 131404313421301 is 103124313404131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 37424356827025 + 93979956594276 = 6117545^2 + 9694326^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131404313421301 is a prime.

It is a super-2 number, since 2×131404313421301² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131404313421371) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 581435015026 + ... + 581435015251.

It is an arithmetic number, because the mean of its divisors is an integer number (33141795862923).

Almost surely, 2^{131404313421301} is an apocalyptic number.

It is an amenable number.

131404313421301 is a deficient number, since it is larger than the sum of its proper divisors (1162870030391).

131404313421301 is a wasteful number, since it uses less digits than its factorization.

131404313421301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1162870030390.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 131404313421301 its reverse (103124313404131), we get a palindrome (234528626825432).

The spelling of 131404313421301 in words is "one hundred thirty-one trillion, four hundred four billion, three hundred thirteen million, four hundred twenty-one thousand, three hundred one".