Base | Representation |
---|---|
bin | 11101111000001011110100… |
… | …100010111000110110111010 |
3 | 122020021010112211212200201122 |
4 | 131320023310202320312322 |
5 | 114210412033023142224 |
6 | 1143250152235345242 |
7 | 36451435564613660 |
oct | 3570136442706672 |
9 | 566233484780648 |
10 | 131404332240314 |
11 | 3896229a933811 |
12 | 128a3058bb2222 |
13 | 58424b5889163 |
14 | 2464009cc4c30 |
15 | 102d1dcc0a15e |
hex | 7782f48b8dba |
131404332240314 has 8 divisors (see below), whose sum is σ = 225264569554848. Its totient is φ = 56316142388700.
The previous prime is 131404332240287. The next prime is 131404332240331. The reversal of 131404332240314 is 413042233404131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4693011865712 + ... + 4693011865739.
It is an arithmetic number, because the mean of its divisors is an integer number (28158071194356).
Almost surely, 2131404332240314 is an apocalyptic number.
131404332240314 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
131404332240314 is a deficient number, since it is larger than the sum of its proper divisors (93860237314534).
131404332240314 is an equidigital number, since it uses as much as digits as its factorization.
131404332240314 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9386023731460.
The product of its (nonzero) digits is 82944, while the sum is 35.
Adding to 131404332240314 its reverse (413042233404131), we get a palindrome (544446565644445).
The spelling of 131404332240314 in words is "one hundred thirty-one trillion, four hundred four billion, three hundred thirty-two million, two hundred forty thousand, three hundred fourteen".
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