Base | Representation |
---|---|
bin | 11101111000001011111010… |
… | …100000011000001001010111 |
3 | 122020021010210211001110211022 |
4 | 131320023322200120021113 |
5 | 114210412234123322320 |
6 | 1143250210211031355 |
7 | 36451441220626544 |
oct | 3570137240301127 |
9 | 566233724043738 |
10 | 131404432245335 |
11 | 38962341328a97 |
12 | 128a308659b55b |
13 | 5842500502022 |
14 | 24640192b7bcb |
15 | 102d1e68b1325 |
hex | 7782fa818257 |
131404432245335 has 4 divisors (see below), whose sum is σ = 157685318694408. Its totient is φ = 105123545796264.
The previous prime is 131404432245329. The next prime is 131404432245343. The reversal of 131404432245335 is 533542234404131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131404432245335 - 24 = 131404432245319 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13140443224529 + ... + 13140443224538.
It is an arithmetic number, because the mean of its divisors is an integer number (39421329673602).
Almost surely, 2131404432245335 is an apocalyptic number.
131404432245335 is a deficient number, since it is larger than the sum of its proper divisors (26280886449073).
131404432245335 is an equidigital number, since it uses as much as digits as its factorization.
131404432245335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26280886449072.
The product of its (nonzero) digits is 2073600, while the sum is 44.
Adding to 131404432245335 its reverse (533542234404131), we get a palindrome (664946666649466).
The spelling of 131404432245335 in words is "one hundred thirty-one trillion, four hundred four billion, four hundred thirty-two million, two hundred forty-five thousand, three hundred thirty-five".
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