Base | Representation |
---|---|
bin | 11101111000001011111010… |
… | …100001011001101000000101 |
3 | 122020021010210211120002201212 |
4 | 131320023322201121220011 |
5 | 114210412234210413131 |
6 | 1143250210220501205 |
7 | 36451441223124515 |
oct | 3570137241315005 |
9 | 566233724502655 |
10 | 131404432513541 |
11 | 389623414a1550 |
12 | 128a30866aa805 |
13 | 5842500597125 |
14 | 2464019347845 |
15 | 102d1e6915a2b |
hex | 7782fa859a05 |
131404432513541 has 8 divisors (see below), whose sum is σ = 144299629685568. Its totient is φ = 118667458620000.
The previous prime is 131404432513517. The next prime is 131404432513559. The reversal of 131404432513541 is 145315234404131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 131404432513541 - 210 = 131404432512517 is a prime.
It is a super-2 number, since 2×1314044325135412 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131404432513241) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 39555817880 + ... + 39555821201.
It is an arithmetic number, because the mean of its divisors is an integer number (18037453710696).
Almost surely, 2131404432513541 is an apocalyptic number.
131404432513541 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
131404432513541 is a deficient number, since it is larger than the sum of its proper divisors (12895197172027).
131404432513541 is a wasteful number, since it uses less digits than its factorization.
131404432513541 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 79111639243.
The product of its (nonzero) digits is 345600, while the sum is 41.
Adding to 131404432513541 its reverse (145315234404131), we get a palindrome (276719666917672).
The spelling of 131404432513541 in words is "one hundred thirty-one trillion, four hundred four billion, four hundred thirty-two million, five hundred thirteen thousand, five hundred forty-one".
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