Base | Representation |
---|---|
bin | 10011000111110011111… |
… | …000001101111101110010 |
3 | 11122121210212101001010012 |
4 | 103013303320031331302 |
5 | 133012141444013114 |
6 | 2443400321534522 |
7 | 163636356012365 |
oct | 23076370157562 |
9 | 4577725331105 |
10 | 1314056626034 |
11 | 4673197873a9 |
12 | 19280aaa4442 |
13 | 96bb8371639 |
14 | 4785a3a20dc |
15 | 242acee163e |
hex | 131f3e0df72 |
1314056626034 has 8 divisors (see below), whose sum is σ = 1974131440128. Its totient is φ = 656012812660.
The previous prime is 1314056626031. The next prime is 1314056626037. The reversal of 1314056626034 is 4306266504131.
It is an interprime number because it is at equal distance from previous prime (1314056626031) and next prime (1314056626037).
It is a sphenic number, since it is the product of 3 distinct primes.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 1314056625982 and 1314056626000.
It is not an unprimeable number, because it can be changed into a prime (1314056626031) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 507748562 + ... + 507751149.
It is an arithmetic number, because the mean of its divisors is an integer number (246766430016).
Almost surely, 21314056626034 is an apocalyptic number.
1314056626034 is a deficient number, since it is larger than the sum of its proper divisors (660074814094).
1314056626034 is a wasteful number, since it uses less digits than its factorization.
1314056626034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1015500360.
The product of its (nonzero) digits is 311040, while the sum is 41.
The spelling of 1314056626034 in words is "one trillion, three hundred fourteen billion, fifty-six million, six hundred twenty-six thousand, thirty-four".
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