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1314102432451 = 4447295503133
BaseRepresentation
bin10011000111110110100…
…110111101001011000011
311122121221001120020201011
4103013312212331023003
5133012240210314301
62443405035421351
7163640453242654
oct23076646751303
94577831506634
101314102432451
11467342623446
121928222b4857
1396bc49bc023
14478624c752b
15242b203da51
hex131f69bd2c3

1314102432451 has 4 divisors (see below), whose sum is σ = 1314397940032. Its totient is φ = 1313806924872.

The previous prime is 1314102432443. The next prime is 1314102432463. The reversal of 1314102432451 is 1542342014131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1314102432451 - 23 = 1314102432443 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1314102432551) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 147747120 + ... + 147756013.

It is an arithmetic number, because the mean of its divisors is an integer number (328599485008).

Almost surely, 21314102432451 is an apocalyptic number.

1314102432451 is a deficient number, since it is larger than the sum of its proper divisors (295507581).

1314102432451 is an equidigital number, since it uses as much as digits as its factorization.

1314102432451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 295507580.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 1314102432451 its reverse (1542342014131), we get a palindrome (2856444446582).

The spelling of 1314102432451 in words is "one trillion, three hundred fourteen billion, one hundred two million, four hundred thirty-two thousand, four hundred fifty-one".

Divisors: 1 4447 295503133 1314102432451