131410401402041 has 4 divisors (see below), whose sum is σ = 131410425207012. Its totient is φ = 131410377597072.

The previous prime is 131410401402031. The next prime is 131410401402047. The reversal of 131410401402041 is 140204104014131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 13223150413225 + 118187250988816 = 3636365^2 + 10871396^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131410401402041 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 131410401402041.

It is not an unprimeable number, because it can be changed into a prime (131410401402047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1146851 + ... + 16252263.

It is an arithmetic number, because the mean of its divisors is an integer number (32852606301753).

Almost surely, 2^{131410401402041} is an apocalyptic number.

It is an amenable number.

131410401402041 is a deficient number, since it is larger than the sum of its proper divisors (23804971).

131410401402041 is an equidigital number, since it uses as much as digits as its factorization.

131410401402041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23804970.

The product of its (nonzero) digits is 1536, while the sum is 26.

Adding to 131410401402041 its reverse (140204104014131), we get a palindrome (271614505416172).

The spelling of 131410401402041 in words is "one hundred thirty-one trillion, four hundred ten billion, four hundred one million, four hundred two thousand, forty-one".