131410403301421 has 4 divisors (see below), whose sum is σ = 139140427025052. Its totient is φ = 123680379577792.

The previous prime is 131410403301407. The next prime is 131410403301451. The reversal of 131410403301421 is 124103304014131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 64759278709225 + 66651124592196 = 8047315^2 + 8164014^2 .

It is a cyclic number.

It is not a de Polignac number, because 131410403301421 - 2¹⁷ = 131410403170349 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131410403301421.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131410403301451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3865011861790 + ... + 3865011861823.

It is an arithmetic number, because the mean of its divisors is an integer number (34785106756263).

Almost surely, 2^{131410403301421} is an apocalyptic number.

It is an amenable number.

131410403301421 is a deficient number, since it is larger than the sum of its proper divisors (7730023723631).

131410403301421 is an equidigital number, since it uses as much as digits as its factorization.

131410403301421 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7730023723630.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 131410403301421 its reverse (124103304014131), we get a palindrome (255513707315552).

The spelling of 131410403301421 in words is "one hundred thirty-one trillion, four hundred ten billion, four hundred three million, three hundred one thousand, four hundred twenty-one".