Base | Representation |
---|---|
bin | 1011111100111010001100… |
… | …1101010110011011111011 |
3 | 1201112021022220001122012001 |
4 | 2333032203031112123323 |
5 | 3210300324021110233 |
6 | 43540524544401431 |
7 | 2524260204504214 |
oct | 277164315263373 |
9 | 51467286048161 |
10 | 13141043144443 |
11 | 42070a32a5785 |
12 | 15829a4916277 |
13 | 74426c6b2436 |
14 | 33605bdd240b |
15 | 17bc66c5d27d |
hex | bf3a33566fb |
13141043144443 has 4 divisors (see below), whose sum is σ = 13235583023320. Its totient is φ = 13046503265568.
The previous prime is 13141043144401. The next prime is 13141043144447. The reversal of 13141043144443 is 34444134014131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13141043144443 - 29 = 13141043143931 is a prime.
It is a super-2 number, since 2×131410431444432 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13141043144447) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47269939230 + ... + 47269939507.
It is an arithmetic number, because the mean of its divisors is an integer number (3308895755830).
Almost surely, 213141043144443 is an apocalyptic number.
13141043144443 is a deficient number, since it is larger than the sum of its proper divisors (94539878877).
13141043144443 is an equidigital number, since it uses as much as digits as its factorization.
13141043144443 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 94539878876.
The product of its (nonzero) digits is 110592, while the sum is 37.
Adding to 13141043144443 its reverse (34444134014131), we get a palindrome (47585177158574).
The spelling of 13141043144443 in words is "thirteen trillion, one hundred forty-one billion, forty-three million, one hundred forty-four thousand, four hundred forty-three".
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