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13141043144447 is a prime number
BaseRepresentation
bin1011111100111010001100…
…1101010110011011111111
31201112021022220001122012012
42333032203031112123333
53210300324021110242
643540524544401435
72524260204504221
oct277164315263377
951467286048165
1013141043144447
1142070a32a5789
1215829a491627b
1374426c6b243a
1433605bdd2411
1517bc66c5d282
hexbf3a33566ff

13141043144447 has 2 divisors, whose sum is σ = 13141043144448. Its totient is φ = 13141043144446.

The previous prime is 13141043144401. The next prime is 13141043144483. The reversal of 13141043144447 is 74444134014131.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13141043144447 - 220 = 13141042095871 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13141043144497) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570521572223 + 6570521572224.

It is an arithmetic number, because the mean of its divisors is an integer number (6570521572224).

Almost surely, 213141043144447 is an apocalyptic number.

13141043144447 is a deficient number, since it is larger than the sum of its proper divisors (1).

13141043144447 is an equidigital number, since it uses as much as digits as its factorization.

13141043144447 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 258048, while the sum is 41.

Adding to 13141043144447 its reverse (74444134014131), we get a palindrome (87585177158578).

The spelling of 13141043144447 in words is "thirteen trillion, one hundred forty-one billion, forty-three million, one hundred forty-four thousand, four hundred forty-seven".