Base | Representation |
---|---|
bin | 11101111000010010001000… |
… | …100011001001100100000000 |
3 | 122020021210001020000000010102 |
4 | 131320102020203021210000 |
5 | 114211014423214212000 |
6 | 1143253233005021532 |
7 | 36452065550323412 |
oct | 3570221043114400 |
9 | 566253036000112 |
10 | 131411110304000 |
11 | 3896515898233a |
12 | 128a442ab548a8 |
13 | 5843025bc7227 |
14 | 246449018c9b2 |
15 | 102d487cd53d5 |
hex | 7784888c9900 |
131411110304000 has 576 divisors, whose sum is σ = 353784148623360. Its totient is φ = 48459556454400.
The previous prime is 131411110303939. The next prime is 131411110304009. The reversal of 131411110304000 is 403011114131.
It is a super-2 number, since 2×1314111103040002 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is not an unprimeable number, because it can be changed into a prime (131411110304009) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 5457939962 + ... + 5457964038.
It is an arithmetic number, because the mean of its divisors is an integer number (614208591360).
Almost surely, 2131411110304000 is an apocalyptic number.
131411110304000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131411110304000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (176892074311680).
131411110304000 is an abundant number, since it is smaller than the sum of its proper divisors (222373038319360).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131411110304000 is a wasteful number, since it uses less digits than its factorization.
131411110304000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 24331 (or 24307 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 131411110304000 its reverse (403011114131), we get a palindrome (131814121418131).
The spelling of 131411110304000 in words is "one hundred thirty-one trillion, four hundred eleven billion, one hundred ten million, three hundred four thousand".
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