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131411154053 = 619212295887
BaseRepresentation
bin111101001100010110…
…1110001010010000101
3110120012021021022001202
41322120231301102011
54123112223412203
6140211445032245
712331330244054
oct1723055612205
9416167238052
10131411154053
1150805197053
12215753b5685
13c51335a22a
146508a8239b
153641bad388
hex1e98b71485

131411154053 has 4 divisors (see below), whose sum is σ = 131623450560. Its totient is φ = 131198857548.

The previous prime is 131411154019. The next prime is 131411154067. The reversal of 131411154053 is 350451114131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131411154053 - 26 = 131411153989 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131411154253) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 106147325 + ... + 106148562.

It is an arithmetic number, because the mean of its divisors is an integer number (32905862640).

Almost surely, 2131411154053 is an apocalyptic number.

It is an amenable number.

131411154053 is a deficient number, since it is larger than the sum of its proper divisors (212296507).

131411154053 is an equidigital number, since it uses as much as digits as its factorization.

131411154053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 212296506.

The product of its (nonzero) digits is 3600, while the sum is 29.

Adding to 131411154053 its reverse (350451114131), we get a palindrome (481862268184).

The spelling of 131411154053 in words is "one hundred thirty-one billion, four hundred eleven million, one hundred fifty-four thousand, fifty-three".

Divisors: 1 619 212295887 131411154053