Base | Representation |
---|---|
bin | 11101111000010010100111… |
… | …000011000111111000111011 |
3 | 122020021211100212211222010220 |
4 | 131320102213003013320323 |
5 | 114211022000213032420 |
6 | 1143253355444311123 |
7 | 36452114332562121 |
oct | 3570224703077073 |
9 | 566254325758126 |
10 | 131411622002235 |
11 | 389653a07a9843 |
12 | 128a45523a24a3 |
13 | 58430a7c16b53 |
14 | 24644dc10b911 |
15 | 102d4b7bae840 |
hex | 7784a70c7e3b |
131411622002235 has 8 divisors (see below), whose sum is σ = 210258595203600. Its totient is φ = 70086198401184.
The previous prime is 131411622002233. The next prime is 131411622002237. The reversal of 131411622002235 is 532200226114131.
It is an interprime number because it is at equal distance from previous prime (131411622002233) and next prime (131411622002237).
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 131411622002235 - 21 = 131411622002233 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131411622002196 and 131411622002205.
It is not an unprimeable number, because it can be changed into a prime (131411622002233) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4380387400060 + ... + 4380387400089.
It is an arithmetic number, because the mean of its divisors is an integer number (26282324400450).
Almost surely, 2131411622002235 is an apocalyptic number.
131411622002235 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
131411622002235 is a deficient number, since it is larger than the sum of its proper divisors (78846973201365).
131411622002235 is an equidigital number, since it uses as much as digits as its factorization.
131411622002235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8760774800157.
The product of its (nonzero) digits is 17280, while the sum is 33.
Adding to 131411622002235 its reverse (532200226114131), we get a palindrome (663611848116366).
The spelling of 131411622002235 in words is "one hundred thirty-one trillion, four hundred eleven billion, six hundred twenty-two million, two thousand, two hundred thirty-five".
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