Base | Representation |
---|---|
bin | 11101111000010010100111… |
… | …000011000111111000011101 |
3 | 122020021211100212211222002210 |
4 | 131320102213003013320131 |
5 | 114211022000213032310 |
6 | 1143253355444311033 |
7 | 36452114332562046 |
oct | 3570224703077035 |
9 | 566254325758083 |
10 | 131411622002205 |
11 | 389653a07a9816 |
12 | 128a45523a2479 |
13 | 58430a7c16b2c |
14 | 24644dc10b8cd |
15 | 102d4b7bae820 |
hex | 7784a70c7e1d |
131411622002205 has 16 divisors (see below), whose sum is σ = 210744180884160. Its totient is φ = 69924336507648.
The previous prime is 131411622002197. The next prime is 131411622002233. The reversal of 131411622002205 is 502200226114131.
It is not a de Polignac number, because 131411622002205 - 23 = 131411622002197 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10116361635 + ... + 10116374624.
It is an arithmetic number, because the mean of its divisors is an integer number (13171511305260).
Almost surely, 2131411622002205 is an apocalyptic number.
131411622002205 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
131411622002205 is a deficient number, since it is larger than the sum of its proper divisors (79332558881955).
131411622002205 is a wasteful number, since it uses less digits than its factorization.
131411622002205 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20232736700.
The product of its (nonzero) digits is 5760, while the sum is 30.
Adding to 131411622002205 its reverse (502200226114131), we get a palindrome (633611848116336).
The spelling of 131411622002205 in words is "one hundred thirty-one trillion, four hundred eleven billion, six hundred twenty-two million, two thousand, two hundred five".
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