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1314120214131 = 32239195640943
BaseRepresentation
bin10011000111110111101…
…010110010011001110011
311122121222022000122120220
4103013313222302121303
5133012304233323011
62443410512504123
7163641060342414
oct23076752623163
94577868018526
101314120214131
1146735166904a
1219282824b043
1396bc85a682a
14478649d580b
15242b38a2506
hex131f7ab2673

1314120214131 has 8 divisors (see below), whose sum is σ = 1752942858240. Its totient is φ = 875688856392.

The previous prime is 1314120214123. The next prime is 1314120214177.

1314120214131 is nontrivially palindromic in base 10.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1314120214131 - 23 = 1314120214123 is a prime.

It is a super-2 number, since 2×13141202141312 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1314120210131) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 97813755 + ... + 97827188.

It is an arithmetic number, because the mean of its divisors is an integer number (219117857280).

Almost surely, 21314120214131 is an apocalyptic number.

1314120214131 is a deficient number, since it is larger than the sum of its proper divisors (438822644109).

1314120214131 is a wasteful number, since it uses less digits than its factorization.

1314120214131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 195643185.

The product of its (nonzero) digits is 576, while the sum is 24.

It can be divided in two parts, 1314120 and 214131, that added together give a palindrome (1528251).

The spelling of 1314120214131 in words is "one trillion, three hundred fourteen billion, one hundred twenty million, two hundred fourteen thousand, one hundred thirty-one".

Divisors: 1 3 2239 6717 195640943 586922829 438040071377 1314120214131