13141232502434 has 4 divisors (see below), whose sum is σ = 19711848753654. Its totient is φ = 6570616251216.

The previous prime is 13141232502397. The next prime is 13141232502449. The reversal of 13141232502434 is 43420523214131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 8669509026409 + 4471723476025 = 2944403^2 + 2114645^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13141232502394 and 13141232502403.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3285308125607 + ... + 3285308125610.

Almost surely, 2^{13141232502434} is an apocalyptic number.

13141232502434 is a deficient number, since it is larger than the sum of its proper divisors (6570616251220).

13141232502434 is an equidigital number, since it uses as much as digits as its factorization.

13141232502434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6570616251219.

The product of its (nonzero) digits is 69120, while the sum is 35.

Adding to 13141232502434 its reverse (43420523214131), we get a palindrome (56561755716565).

The spelling of 13141232502434 in words is "thirteen trillion, one hundred forty-one billion, two hundred thirty-two million, five hundred two thousand, four hundred thirty-four".