Base | Representation |
---|---|
bin | 11101111000010011010111… |
… | …011001101110000110101101 |
3 | 122020021220110102022201120220 |
4 | 131320103113121232012231 |
5 | 114211030130401413201 |
6 | 1143254012144001553 |
7 | 36452143413120264 |
oct | 3570232731560655 |
9 | 566256412281526 |
10 | 131412433232301 |
11 | 3896577770aa11 |
12 | 128a473a0002b9 |
13 | 58431a6ccc440 |
14 | 2464577b5b5db |
15 | 102d514004036 |
hex | 7784d766e1ad |
131412433232301 has 16 divisors (see below), whose sum is σ = 189082239556224. Its totient is φ = 80703133838784.
The previous prime is 131412433232293. The next prime is 131412433232347. The reversal of 131412433232301 is 103232334214131.
It is not a de Polignac number, because 131412433232301 - 23 = 131412433232293 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131412433237301) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3459477486 + ... + 3459515471.
It is an arithmetic number, because the mean of its divisors is an integer number (11817639972264).
Almost surely, 2131412433232301 is an apocalyptic number.
It is an amenable number.
131412433232301 is a deficient number, since it is larger than the sum of its proper divisors (57669806323923).
131412433232301 is a wasteful number, since it uses less digits than its factorization.
131412433232301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6918993460.
The product of its (nonzero) digits is 31104, while the sum is 33.
Adding to 131412433232301 its reverse (103232334214131), we get a palindrome (234644767446432).
The spelling of 131412433232301 in words is "one hundred thirty-one trillion, four hundred twelve billion, four hundred thirty-three million, two hundred thirty-two thousand, three hundred one".
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