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1314124650155 = 5454957776419
BaseRepresentation
bin10011000111110111111…
…011101101011010101011
311122121222121101000200002
4103013313323231122223
5133012311402301110
62443411151533215
7163641143136422
oct23076773553253
94577877330602
101314124650155
11467354118989
1219282982a20b
1396bc949a9b5
144786542c2b9
15242b3e7baa5
hex131f7eed6ab

1314124650155 has 8 divisors (see below), whose sum is σ = 1577296266000. Its totient is φ = 1051068596256.

The previous prime is 1314124650131. The next prime is 1314124650229. The reversal of 1314124650155 is 5510564214131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1314124650155 - 28 = 1314124649899 is a prime.

It is a super-2 number, since 2×13141246501552 (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 28865465 + ... + 28910954.

It is an arithmetic number, because the mean of its divisors is an integer number (197162033250).

Almost surely, 21314124650155 is an apocalyptic number.

1314124650155 is a deficient number, since it is larger than the sum of its proper divisors (263171615845).

1314124650155 is an equidigital number, since it uses as much as digits as its factorization.

1314124650155 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 57780973.

The product of its (nonzero) digits is 72000, while the sum is 38.

Adding to 1314124650155 its reverse (5510564214131), we get a palindrome (6824688864286).

The spelling of 1314124650155 in words is "one trillion, three hundred fourteen billion, one hundred twenty-four million, six hundred fifty thousand, one hundred fifty-five".

Divisors: 1 5 4549 22745 57776419 288882095 262824930031 1314124650155