1314130353035 has 4 divisors (see below), whose sum is σ = 1576956423648. Its totient is φ = 1051304282424.

The previous prime is 1314130353017. The next prime is 1314130353047. The reversal of 1314130353035 is 5303530314131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1314130353035 - 2²² = 1314126158731 is a prime.

It is a super-2 number, since 2×1314130353035² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1314130352992 and 1314130353010.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131413035299 + ... + 131413035308.

It is an arithmetic number, because the mean of its divisors is an integer number (394239105912).

Almost surely, 2^{1314130353035} is an apocalyptic number.

1314130353035 is a deficient number, since it is larger than the sum of its proper divisors (262826070613).

1314130353035 is an equidigital number, since it uses as much as digits as its factorization.

1314130353035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 262826070612.

The product of its (nonzero) digits is 24300, while the sum is 32.

Adding to 1314130353035 its reverse (5303530314131), we get a palindrome (6617660667166).

The spelling of 1314130353035 in words is "one trillion, three hundred fourteen billion, one hundred thirty million, three hundred fifty-three thousand, thirty-five".