Search a number
-
+
131413044134042 = 21125096323801597
BaseRepresentation
bin11101111000010011111011…
…110100001000000010011010
3122020021222000222211202020022
4131320103323310020002122
5114211032403244242132
61143254152525430442
736452164511523026
oct3570237364100232
9566258028752208
10131413044134042
1138965a60534490
12128a488a70b422
135843273744168
1424645d4d41386
15102d54c976e12
hex7784fbd0809a

131413044134042 has 16 divisors (see below), whose sum is σ = 215040392656992. Its totient is φ = 59732961353520.

The previous prime is 131413044134039. The next prime is 131413044134107. The reversal of 131413044134042 is 240431440314131.

It is a junction number, because it is equal to n+sod(n) for n = 131413044133993 and 131413044134011.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6379613 + ... + 17421984.

It is an arithmetic number, because the mean of its divisors is an integer number (13440024541062).

Almost surely, 2131413044134042 is an apocalyptic number.

131413044134042 is a deficient number, since it is larger than the sum of its proper divisors (83627348522950).

131413044134042 is a wasteful number, since it uses less digits than its factorization.

131413044134042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24052573.

The product of its (nonzero) digits is 55296, while the sum is 35.

Adding to 131413044134042 its reverse (240431440314131), we get a palindrome (371844484448173).

The spelling of 131413044134042 in words is "one hundred thirty-one trillion, four hundred thirteen billion, forty-four million, one hundred thirty-four thousand, forty-two".

Divisors: 1 2 11 22 250963 501926 2760593 5521186 23801597 47603194 261817567 523635134 5973320187911 11946640375822 65706522067021 131413044134042