131413101040433 has 4 divisors (see below), whose sum is σ = 133892593512948. Its totient is φ = 128933608567920.

The previous prime is 131413101040379. The next prime is 131413101040477. The reversal of 131413101040433 is 334040101314131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 74672013842209 + 56741087198224 = 8641297^2 + 7532668^2 .

It is a cyclic number.

It is not a de Polignac number, because 131413101040433 - 2⁶ = 131413101040369 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131413101040396 and 131413101040405.

It is not an unprimeable number, because it can be changed into a prime (131413101090433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1239746236178 + ... + 1239746236283.

It is an arithmetic number, because the mean of its divisors is an integer number (33473148378237).

Almost surely, 2^{131413101040433} is an apocalyptic number.

It is an amenable number.

131413101040433 is a deficient number, since it is larger than the sum of its proper divisors (2479492472515).

131413101040433 is an equidigital number, since it uses as much as digits as its factorization.

131413101040433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2479492472514.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 131413101040433 its reverse (334040101314131), we get a palindrome (465453202354564).

The spelling of 131413101040433 in words is "one hundred thirty-one trillion, four hundred thirteen billion, one hundred one million, forty thousand, four hundred thirty-three".